F(-7)=3x^2+4x+19

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Solution for F(-7)=3x^2+4x+19 equation: 



(-7)=3F^2+4F+19

We move all terms to the left:

(-7)-(3F^2+4F+19)=0

We add all the numbers together, and all the variables

-(3F^2+4F+19)-7=0

We get rid of parentheses

-3F^2-4F-19-7=0

We add all the numbers together, and all the variables

-3F^2-4F-26=0

a = -3; b = -4; c = -26;
Δ = b2-4ac
Δ = -42-4·(-3)·(-26)
Δ = -296
Delta is less than zero, so there is no solution for the equation

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